Specific Latent Heat of Fusion problem

AI Thread Summary
To calculate the heat energy required to change 200 g of water at 25 degrees Celsius into ice at -4 degrees Celsius, the process involves three stages: cooling the water to 0 degrees Celsius, freezing it into ice, and then cooling the ice to -4 degrees Celsius. The relevant equation is Q = mc(Tf-Ti) + MLf + mc(Tf-Ti), where Q represents heat energy, m is mass, c is specific heat capacity, Tf is final temperature, Ti is initial temperature, and Lf is latent heat of fusion. The user initially struggled with whether to consider the water cooling to 0 degrees Celsius or -4 degrees Celsius, but later clarified the three stages of the process. Understanding these stages is crucial for accurately calculating the total heat energy removed. The discussion highlights the importance of breaking down complex thermal processes into manageable steps.
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Homework Statement



An ice tray containing 200 g of water at 25 degrees celecius is placed in the freezer. How much heat energy has to be removed to change the water into ice at -4 degrees celcius?

Homework Equations



Q= mc(Tf-Ti) + MLf + mc(Tf-Ti)

The Attempt at a Solution


I know that the water is changing into ice however I am stumped because I don't know if the water is turning to -4 degrees celcius or 0 degrees celcius?

Any help will be muchly appreciated
Thankyou
 
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Break it into 3 stages.

The water drops to freezing point. Then it freezes into ice. Then it drops to -4 degrees.
 
i get it now! Thankyou soo much!
Kind regards:)
 
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