(SPECTROSCOPY) chromium(III) absorb light

AI Thread Summary
Chromium(III) absorbs light due to the excitation of electrons when photons are absorbed by the atom. This process elevates electrons to higher energy orbitals. Subsequently, the excited electrons do not remain in these higher states and return to lower energy levels. During this transition, a new photon is emitted, which occurs in a random manner. Understanding this atomic-level interaction explains the light absorption characteristics of chromium(III).
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Homework Statement



Why does chromium(III) absorb light? Explain what is happening on an atomic level.

-> I don't really get this problem. Can you help me out...? Please...


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The Attempt at a Solution

 
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What happens when a photon "excites" an electron in an atom?
 
QuarkCharmer said:
What happens when a photon "excites" an electron in an atom?

=>>> I wrote the answer for this question like this.

Because the photons are absorbed by an atom, an election attains a higher energy orbital. The electron won't stay up there. The electron falls to a lower energy level and a new photon is emitted. The photon is emitted in a more or less random reaction.
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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