Specular Reflection for 3-D Particle Collision

  • Thread starter Thread starter Disinterred
  • Start date Start date
  • Tags Tags
    Reflection
AI Thread Summary
The discussion focuses on calculating the spherical polar coordinates (θc, φc) for a particle undergoing specular reflection after colliding with a cube face. The initial angles (θi, φi) describe the particle's trajectory, and the participant initially believes that θ should follow the law of reflection while φ could vary freely. However, upon further reflection, they conclude that both angles must be determined based on the angle between the incoming ray and the normal of the cube face. This realization emphasizes the need to accurately compute the outgoing direction in 3-D space. The participant seeks confirmation on this approach and acknowledges the simplicity of the solution.
Disinterred
Messages
38
Reaction score
0
I am writing code for a particle simulation and I have this question:

Homework Statement



A particle, with initial coordinates (xi,yi,zi) w.r.t a fixed origin in a global rectangular coordinate system, is traveling toward one of the faces of a cube with a speed whose direction can be described by the standard spherical polar angles (θii) w.r.t a local origin at the initial coordinates (xi,yi,zi).

Now, say it hits the cubic face at a point (xc,yc,zc). If the particle is to undergo specular reflection, what are the spherical polar coordinates (θcc) w.r.t a local origin at the point (xc,yc,zc) which describe the direction of the velocity it reflects at? (in terms of the original angles)

Essentially, for a 2-D collision, I know that the particle must satisfy the usual law of reflection if we want specular reflection and thus we can get the new angle easily. But now in 3-D, there are two angles, so I am not sure what specular reflection would entail?

Homework Equations



θ and φ are the usual spherical polar angles,

0° ≤ θ ≤ 180° (pi rad)
0° ≤ φ < 360° (2pi rad)

The Attempt at a Solution



The only solution that makes sense to me is that the θ angle will obey the usual law of reflection, but the φ angle has no restrictions and can be anything from 0 to 2pi
 
Last edited:
Physics news on Phys.org
Hmmm I typed all of that out and I think that helped me figure it out.

Phi would be the same, theta would have to satisfy the law of reflection along the plane formed by the incoming ray vector and the normal vector. This is of course a general solution and would work for any object (cube, triangle, sphere, etc). But if anyone thinks this is wrong/thinks it is right please tell me.

EDIT: On second thought, I do not think this is correct. I think what I need to do is find the angle between the normal of the face and the incoming ray and then find the corresponding spherical polar angles to describe the outgoing ray. This seems rather obvious and trivial, not sure why I never thought of it before.
 
Last edited:
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top