Speed at which to hurl a projectile?

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The discussion centers on calculating the initial velocity of a stone hurled by Archimedes' catapult, which can launch a 77 kg stone 180 m. The mass of the stone is deemed irrelevant due to the neglect of wind resistance. The optimal launch angle for maximum range is identified as 45 degrees, which is crucial for determining the initial velocity. The textbook indicates that the initial velocity must be greater than 42 m/s for effective projectile motion. The problem was ultimately resolved by understanding the relationship between launch angle and initial velocity.
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Homework Statement


The Archimedes' catapult could hurl a 77 kg stone a distance of 180 m. What was the stone's initial velocity as it left the catapult? The wind resistance is assumed to be insignificant.


Homework Equations


y = v_y0 t - (1/2) g t^2
x = v_x0 t

The Attempt at a Solution


I think the mass of the stone is irrelevant as wind resistance is not taken into account. The problem would be easy if I knew the angle at which the catapult was fired. Here, however, both the angle and the initial velocity of the projectile are unknown. The answer provided by the textbook says the velocity is > 42 m/s. So clearly the 42 m/s is the initial velocity at the optimal angle and if you change the angle, you have to make up for it by launching at a greater initial velocity. I think the solution might have something to do with a derivative function, but other than that, I'm completely lost.
 
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There is an optimal angle, which gives the maximum range for a projectile launched from ground level. Perhaps your book has a discussion of "range" in the section on projectile motion?
 
Thanks. I figured it out now. So apparently the optimal angle is always 45 degrees.
 
Yes. Glad it worked out.
 
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