Speed distance and not a lot of hair left

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Homework Help Overview

The problem involves calculating the time it takes for a ball to fall 100 meters, given its initial velocity of 72 km/h and the acceleration due to gravity at 10 m/s². The original poster references the equation s = ut + 0.5gt² in their attempt to solve the problem.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of the equation s = ut + 0.5gt² and question the original poster's understanding of the problem. There are inquiries about the difficulty in obtaining the time and suggestions to rearrange the equation to solve for it.

Discussion Status

Some participants have provided guidance on how to approach the problem using the given formula. There is an acknowledgment of the need to convert units from km/h to m/s, and the discussion appears to be focused on clarifying the steps needed to solve the equation rather than reaching a consensus on the solution.

Contextual Notes

There is a mention of unit conversion that may affect the calculations, as the initial velocity is given in kilometers per hour rather than meters per second.

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Homework Statement


a balls inital velocity is 72 km/ph and falls 100 meters with gravity @ 10 meters per second and i need to work out the time it takes to fall to ground. i was given s=ut+0.5*gt^2

Homework Equations


s=ut+0.5gt^2
v^2=u^2+2as
t=(v-u)/a

The Attempt at a Solution



v2=u2+2as
v=squr u^2+2as
v=squr 20^2+2*10*100
v=48.98979486

t=(v-u)/a
t=(48.98979486-20)/10
t=2.898979486 seconds

100=20*2.898979486+0.5*10*2.898979486^2

is this correct??
and is there a way to do this with just the s=ut+0.5at^2 formula ?
 
Last edited:
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hi steveandy2002! :smile:

(try using the X2 button just above the Reply box :wink:)
steveandy2002 said:
a balls inital velocity is 72 kph and falls 100 meters with gravity @ 10 meters per second and i need to work out the time it takes to fall to ground.

and is there a way to do this with just the s=ut+0.5at^2 formula ?

s = 100, u = 72, a = 10 …

what's the difficulty? :confused:
 
tiny-tim said:
hi steveandy2002! :smile:

(try using the X2 button just above the Reply box :wink:)


s = 100, u = 72, a = 10 …

what's the difficulty? :confused:


not sure what you mean, i need to get time not s
 
All you need to do is plug in your known values into s=ut+[itex]\frac{1}{2}[/itex]gt2. Then you move everything to one side and solve the quadratic equation. What are you having issues with?
 
Don't forget to change the units on u from km/hr to m/s.
 

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