- #1

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A)Determine the x component of velocity after 9:01 s. Answer in units of m/s.

B)Find the speed of the particle after 9:01 s.

Answer in units of m/s.

I have found the answer to A as 66.02 but for B isn't the answer 66.02-(-16.32)= 82.32?

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- Thread starter NINHARDCOREFAN
- Start date

- #1

- 116

- 0

A)Determine the x component of velocity after 9:01 s. Answer in units of m/s.

B)Find the speed of the particle after 9:01 s.

Answer in units of m/s.

I have found the answer to A as 66.02 but for B isn't the answer 66.02-(-16.32)= 82.32?

- #2

HallsofIvy

Science Advisor

Homework Helper

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Since the x-component of velocity is initially 20.7 m/s and there is an acceleration of 5.03 m/s

That's not quite what you got. Is your "20:7" something other than "20.7"??

More importantly, you cannot add components like you do for B.

Set up a right triangle with x-component as one leg and y-component as the other. The "speed" is the length of the vector itself- the hypotenuse of your right triangle. Use the Pythagorean theorem to calculate that.

- #3

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should have read my other thread

- #4

HallsofIvy

Science Advisor

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