Speed of Block at Top of Track: Solving Friction Problem

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The discussion focuses on calculating the speed of a block at the top of a vertical circular track, considering the effects of friction. The block, with a mass of 0.5 kg, is initially pushed against a spring and released, achieving a speed of 14 m/s at the bottom of the track. The user initially misapplied energy conservation principles by not correctly accounting for the negative work done by friction. The correct approach involves recognizing that the work done by friction reduces the total mechanical energy, leading to a lower speed at the top of the track. Clarification on the signs in the energy equation is essential for accurate calculations.
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A block of mass .5kg is pushed against a horizontal spring of negligible mass, compressing the spring a distance of Δx (I solved for this and got .421m) as shown in the figure. The spring constant is 553N/m. When released, the block travels along a frictionless horizontal surface to point B, the bottom of the vertical circular track of radius .7m, and continues to move up the track. The speed of the block at the bottom of the track is 14m/s, and the block experiences an average frictional force of 6N while sliding up the track.
What is the speed of the block at the top of the track?
I know that normally the change in kinetic energy is equal to potential energy, but this is the not the case due to friction. This is the formula I used:
(6)(pi)(.7) - (1.4)(9.8)(.5) = .5(.5)v^2 - .5(.5)(14)^2
The 2nd half of the equation is equal to the change in kinetic energy. The 1.4 stuff is equal to the potential energy (m*g*h) But I'm really confused as what to do with the friction. I just multiplied the force of friction with half of the circumference.
I don't know how else to approach this, but I know it's wrong because my answer was 14.9m/s and the speed shouldn't be greater on top than bottom. This is frustrating. Thanks for any help.
 

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You're approach is OK, you are just messing up with signs. The change in energy (KE + PE) between bottom and top equals the work done by friction (which is negative).
 
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