Speed of Boy & Image in Plane Mirror: A,B,C Explained

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When a boy runs parallel to a plane mirror while maintaining a constant distance of 40 meters, the speed of the boy and his image is the same. This is because the image in the mirror moves in direct correlation to the boy's movement, reflecting his speed. If the boy runs towards the mirror, the dynamics change, as the distance to the mirror decreases. However, in this scenario, since the distance remains constant, the image does not gain speed relative to the boy. Thus, the correct answer is that their speeds are equal.
Faris1985
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Q. If a boy is at a distance of 40m from a plane mirror and runs parallel to the plane of the mirror while maintaining the same distance from the mirror what will be the speed of the image and the boy.
A. Same
B. The boy has greater speed than his image
C. The image has greater speed than the boy
Please explain why for each A,B or C.
 
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Faris1985 said:
Please explain why
This is directed at you, not us.
 
Faris1985 said:
Q. If a boy is at a distance of 40m from a plane mirror and runs parallel to the plane of the mirror while maintaining the same distance from the mirror what will be the speed of the image and the boy.
A. Same
B. The boy has greater speed than his image
C. The image has greater speed than the boy
Please explain why for each A,B or C.

Think of it. If the boy runs parallel maintaining a same distance, how would it be different from the same boy running towards the mirror.
Also, think of what the distance of image and object is from the mirror and with respect to each other.
If you do a little pondering, you would answer it.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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