Speed of gas expansion & Size of expansion

AI Thread Summary
The speed of gas expansion depends on the heating rate and the speed of sound in the gas, which varies with temperature. For 100 moles of Argon heated from 25 degrees Celsius to 373 Kelvin, the final volume can be calculated using the ideal gas law, resulting in approximately 30.6 liters per mole at the higher temperature. The time it takes for the gas to reach its final volume is influenced by the initial temperature and the heating method used, such as convection versus uniform heating. The discussion emphasizes that the expansion is proportional to the temperature increase, and the initial conditions are crucial for accurate calculations. Understanding these principles is essential for applications like designing heat exchangers.
s.p.q.r
Messages
25
Reaction score
0
Hi,

Ive a couple of questions.

1) Ideal gases expand according to temperature. But how quickly does it take for it to expand to its destined size?

Lets say if I had 100 moles of Argon and heated it to 373kelvins. How long would it take for it to expand to it final size?

2) To what size will 100 moles of Argon heated to 373kelvins expand? How many litres?

Cheers gang.
 
Physics news on Phys.org
It depends on how quickly you heat it!
And on the speed of sound in the gas, if you start heating one side of the sample the other side will only feel the heat when it has traveled through the sample - which it does at the speed of sound. To make it a little more complicated, the speed of sound in a gas depends on the temperature!

1 mole of an ideal gas is 22.4 litres at 273K (0deg C).
You don't say what temperature you started with 100l at but assuming it was 0degC the final volume = (373/273) * 22.4l/mole = 30.6 l/mole
 
Great, let's say that the entire container was 100deg C automatically. How long would it take to reach its final expansion size?

And for the answer to the second question, i don't understand, could you clarify? Thanks.
 
In real life it is difficult to work out, it depends on the shape of the container the initial temperature of the gas and turbulent motions of the gas.
If you heated the entire container instantly and uniformly you might not get the quickest heating of the gas as there would be no convection.
I'm not being deliberately difficult, designing heat exchangers has been a big field of study for nearly 200years, since the first steam engines.

Ideal gases always occupies 22.4L/mole at 273kelvin/1 atmosphere ( called standard temperature and pressure - STP)
As you heat the gas the expansion in volume is proportional to temperature, so if you double the temperatue you double the volume.

You don't say what temperature you started with 100moles at! If it is currently at 0deg C and you heat it to 100degC it will obviously expand more than if you are currently at 90degC and only heating it another 10deg.
 
Sorry. Its heated to 25 degrees C.
 
You mean heated from 25deg right?

As I said 1 mole at 273K = 22.4L
So 1 mole at 25deg C is ((273+25)/273) * 22.4
and 1 mole at 100deg C is ((273+100)/273) * 22.4
The expansion is the difference.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top