Speed Relative to an Observer on the Ground

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SUMMARY

The discussion centers on calculating the speed of a shuttle orbiting Earth at 7.7 x 103 m/sec, with a distance of 6.7 x 106 m from the observer on the ground. A participant suggests translating the shuttle's speed into angular velocity to determine the relative speed perceived by an observer. This approach involves considering the observer's neck as the rotation point and calculating the speed at which the observer's eyes would rotate, providing a unique perspective on relative motion.

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  • Proficiency in physics equations related to velocity and distance
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ImAlwaysConfu
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Homework Statement



A shuttle is orbitting around the Earth at a velocity of (7.7x10^3) m/sec. The distance between a point on the Earth to the shuttle is (6.7x10^6)m. Calculate the speed of the shuttle relative to an observer on the earth.


Completely lost! I was able to solve the question before it, but I can't find a way to determine the speed. If you need more informatio or if I left anything out, tell me.
 
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Just a thought, this is what I would do, but do not take this as an answer, weight for the real clever guys to come and give an opinion.
Translate the speed of the shuttle to angular velocity. This will give a different speed at different radiu'... If you take the observers neck as its turning point and his eyes is 100mm from the rotation point, what would the speed be at which his eyes will be rotating about his neck, this will be the relative speed to the observer... This is just a thaught and how I will approach this, cheers! Hope you find the answer...
 

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