How Do You Calculate Trip Duration and Distance with Stops and Average Speed?

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To calculate trip duration and distance with stops, the average speed formula v = d/t is essential. The person drives at a constant speed of 90.5 km/h but takes a 22-minute rest, affecting the overall average speed to 73.4 km/h. The equation 90*t = 73.4*(t + 22/60) can be used to relate the distance traveled before and after the stop. By solving this equation, the total time spent on the trip and the distance traveled can be determined. This approach effectively incorporates both driving speed and rest duration into the calculations.
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Homework Statement


A person takes a trip, driving with a constant speed of 90.5 km/h except for a 22.0 min rest stop. If the person's average speed is 73.4 km/h, how much time is spent on the trip and how far does the person travel?


Homework Equations


v = d/t


The Attempt at a Solution


I have no idea how to solve this, other than that I have to plug the values into the average speed formula.
 
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aquapod17 said:

Homework Statement


A person takes a trip, driving with a constant speed of 90.5 km/h except for a 22.0 min rest stop. If the person's average speed is 73.4 km/h, how much time is spent on the trip and how far does the person travel?

Homework Equations


v = d/t

The Attempt at a Solution


I have no idea how to solve this, other than that I have to plug the values into the average speed formula.

From your equation you know that d = V*t

If you hadn't stopped you know that 90.5*t is the distance
But you did stop 22 minutes (which is 22/60 hours) so to do the same distance it was 73.4*(t+22/60)

Since the distance is the same then 90*t =73.4*(t+22/60)

I'm sure you get the idea from here.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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