Spherical cavity electric field

Click For Summary
SUMMARY

The discussion centers on calculating the electric field at point P, located 19.00 m from the center of a solid sphere with a uniformly distributed positive charge of Q = 2800.00 C and a radius of R = 6.00 m, after a spherical cavity of radius R/2 is removed. The principle of superposition is applied, where the electric field is determined by subtracting the field of the smaller cavity from that of the larger sphere using the formula E = KQ/R². The user calculated the charge of the cavity to be Ql = 3500 C but encountered issues with the final electric field calculation.

PREREQUISITES
  • Understanding of electric fields and Coulomb's law
  • Familiarity with the principle of superposition in electrostatics
  • Knowledge of volume charge density and its calculations
  • Ability to manipulate and solve equations involving electric fields
NEXT STEPS
  • Review the concept of electric field due to spherical charge distributions
  • Learn about the principle of superposition in electrostatics
  • Explore the derivation and application of Gauss's law for electric fields
  • Practice problems involving electric fields from multiple charge distributions
USEFUL FOR

This discussion is beneficial for physics students, electrical engineers, and anyone studying electrostatics, particularly those interested in calculating electric fields from complex charge distributions.

GravityGirl
Messages
28
Reaction score
0
A positive charge Q = 2800.00 C is uniformly distributed over the volume of a sphere of radius R = 6.00 m. Suppose a spherical cavity of radius R/2 is cut out of the solid sphere, the center of the cavity being a distance R/2 from the center of the original solid sphere (see figure). The cut-out material and its charge are discarded. What is the magnitude of the electric field produced by this new charge distribution at point P, a distance r = 19.00 m from the center of the original sphere?


so i am going to use the principle of superposition

E=Ebigsphere-Elittlesphere

inorder to find E i must find the charge and i can do so by using porportions

Qb/Vb=Ql/Vl

that is 28000/904.7787=Ql/113.0973 and Ql=3500

so i am going to use the formula E=KQ/R^2 for both big a little spheres

and i have E=(K28000/19^2)-(K3500/16^2)

with this i am not getting the right solution...please help me find where i am going wrong
 
Physics news on Phys.org
Looks OK to me. Where is point P with respect to the two spheres? (Since we don't have the diagram, it's up to you to describe it carefully.)
 
did you ever figure this out?
 

Similar threads

Replies
23
Views
5K
  • · Replies 8 ·
Replies
8
Views
6K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
924
  • · Replies 1 ·
Replies
1
Views
1K
Replies
12
Views
2K
Replies
5
Views
1K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 4 ·
Replies
4
Views
4K
Replies
17
Views
1K