Spherical Co-Ordinate Integral

Ayame17
Messages
43
Reaction score
0

Homework Statement



I'm trying to integrate the following:

\int_0^{2\pi} \int_0^\pi \int_0^r \frac{m^2r}{4\pi} e^{-r(m+iqcos\theta)} sin\theta dr d\theta d\phi


The Attempt at a Solution



Well, the question wasn't just that, my attempt was to get this far!

I know that \int_0^{2\pi} d\phi can just sit off to one side to be put in later, since there is no \phi in the equation. Trying to do the next integral in, however, has proved difficult. I'd have to use integration by parts, since \theta appears twice, but since I have an exponential and sin\theta will just go around to cos\theta and back again, I don't see how it will work. Any help will be appreciated!
 
Physics news on Phys.org
Try substituting x = cos theta (this is a common trick in theoretical physics, so remember it!)
 
I've had a play around with that and, although it gives quite a nice number, I know the answer I need but can't seem to reach it...I've been told that I should get:

F(q^{2})=\frac{m^2}{m^2+q^2}

The problem being, my integral still has an exponential factor - I'm not sure how to make it disappear!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top