Spherical Coordinates (need work double checked please)

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Could someone double check to make sure my calculations are all done right? I've done this problem several times and gotten the same answer but the online submission says its wrong so I need someone else to check my work. thanks!


Homework Statement




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Homework Equations



x = ρ sin(Φ) cos(θ)
y = ρ sin(Φ) sin(θ)
z = p cos(Φ)

The Attempt at a Solution



4z2 = x2+y2

4p 2cos2(Φ) = ρ 2sin2(Φ) cos2(θ) + ρ 2sin2(Φ) sin2(θ)

cos2(Φ) = (ρ 2sin2(Φ) cos2(θ) + ρ 2sin2(Φ) sin2(θ))/ (ρ 2 *4)

***(ρ2's cancel right?)****


so I'm left with for an answer

cos2(Φ) = (sin2(Φ) cos2(θ) + sin2(Φ) sin2(θ))/ 4)
 
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How about using the fact that sin^2(\theta)+ cos^2(\theta)= 1?!
 
I didn't think you could use that when your are talking about two different angles (Φ and θ)?

I tried it anyway though and its a no go...
 
What HallsOfIvy meant was that you should factor out sin2(Φ) in the numerator of your final expression and apply that trigo identity. That will simplify your final answer.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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