Spivak's Calculus Ch.2 Problem 2(i)

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Homework Statement


Find a formula for Σ(2i-1) = 1+3+5+...+(2n-1)

Hint: What does the expression have to do with 1+2+3+...+2n?

Homework Equations

The Attempt at a Solution


I have tried to solve this on my own for about a day now, and I am having trouble understanding the significance of the hint. I don't want an answer, just advice on how to connect the hint and the original expression.[/B]
 
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Hint: let ##S = 1 + 2 + ... + 2n## and ##Y = 1 + 3 + 5 + ... + (2n - 1)##

Then what is ##S - Y##?
 
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axmls said:
Hint: let ##S = 1 + 2 + ... + 2n## and ##Y = 1 + 3 + 5 + ... + (2n - 1)##

Then what is ##S - Y##?

Also: how can you find ##S-Y## in terms of ##n##?
 
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Thanks guys, i finally had an epiphany earlier today with your hints.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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