Spring Constant and Compression Problem

AI Thread Summary
The discussion revolves around calculating the compression of a spring in a dart gun with a spring constant of 62.50 N/m and a potential energy of 0.540 J. Participants clarify that the correct formula to use is the potential energy equation, PE = 1/2 k x^2. One user attempts to solve for x but gets confused with their calculations and suggests incorrect values. Another participant corrects the misunderstanding, emphasizing that the spring's compression cannot be excessively large, and reiterates the proper use of the potential energy formula to find the correct compression value. The focus remains on accurately applying the formula to determine the spring's compression.
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Homework Statement



The potential energy stored in the compressed spring of a dart gun, with a spring constant of 62.50 N/m, is 0.540 J. Find by how much is the spring is compressed.

Homework Equations



I know that F=-k*change in x and also spring= 1/2kx^2

The Attempt at a Solution



Using the two formulas above, i tried 1/2(62.5)(x^2) which is .540? but I am getting the wrong answer.. I also tried x=0 and canceling it. I am not sure what I am doing wrong here.
 
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What number did you get using the 2nd equation (don't use the first)? Please show your math. And why would you try x = 0?
 
I got 9.1125... i did 1/2(62.5)(.540^2)
 
I know X is the "displacement" but I am drawing a blank as to what that number is
 
Are you saying you solved (1/2)(62.6)x2=0.540 for x, and got the wrong answer?
 
I can tell you that the spring is not compressed 9 meters unless you have one big dart gun hehe. Looks like you have your numbers mixed up. Potential energy of a spring is equal to 1/2k*x^2 so your equation should look like this

.540=1/2k*x^2, x is how much the spring is compressed.
 
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