A ping-pong ball weighs 2.5x10^-2N. The ball is placed inside a cup that sits on top of a vertical spring. If the spring is compressed .055m and released, the maximum height above the compressed position that the ball reaches is 2.84m. Neglect air resistance and determine the spring constant.(adsbygoogle = window.adsbygoogle || []).push({});

F= kx => k= F/x (k being the spring constant)

k = 2.5x10^-2 / (2.84 -.055)

= 2.5x10^-2 / 2.745

= .009

This is not the correct answer. Am I using the right formula for the Spring Constant?

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# Homework Help: Spring Constant of ping-pong ball

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