Spring Compression from 8.0kg Mass Sliding 7.00m Down 51deg Incline

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An 8.0 kg block slides down a frictionless incline at a 51-degree angle, traveling 7.00 m before compressing a spring. The force exerted by the block upon contact with the spring is calculated to be approximately 60.928 N. The kinetic energy of the block at the moment of contact needs to be determined to find out how much energy is transferred to the spring. The discussion raises a question about the spring constant, which is not provided in the problem. Understanding these factors is essential to calculate the spring's compression accurately.
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block of mass 8.0 kg slides from rest down a frictionless 51degree incline and is stopped by a strong spring with The block slides 7.00 m from the point of release to the point where it comes to rest against the spring. When the block comes to rest, how far has the spring been compressed?

First i determine the force of the block against the spring when it comes in contact with it
9.8cos(90-51)=7.616x8.0=60.928N
and i determine kinetic energy of the block when it comes in contact with the spring.
Then how do i determine how much the force that the block exerts on the spring and how much the kinetic energy that is trasferred to the spring from the block cause the spring to be compressed?
 
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Is there a spring constant given with the problem?
 

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