Square root of a squared block matrix

  • Thread starter GoodSpirit
  • Start date
  • #1
18
0

Main Question or Discussion Point

Hi everybody,

I’m trying to compute the square root of the following squared block matrix:

[tex]
\begin{equation}
M=\begin{bmatrix}
A &B\\
C &D\\
\end{bmatrix}
\end{equation}
[/tex]

(that is M^(1/2))as function of A,B,C, D wich are all square matrices.

Can you help me?

I sincerely thank you! :)

All the best

GoodSpirit
 

Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
25,832
249
Hi GoodSpirit! :smile:

Have you tried transforming it into the form
[tex]
\begin{equation}
M=\begin{bmatrix}
P &0\\
0 &Q\\
\end{bmatrix}
\end{equation}
[/tex]
 
  • #3
18
0
Hi tiny-tim,

Thank you for answering.
That´s an interesting idea but how do you do that...?
It is not easy...
I must say that there is more...
M is a typical covariance matrix so it is symmetric and semi-positive definite.

A and D are symmetric and positive semi-definite (covariance matrices too) and [tex]B=C^T[/tex] and B is the cross covariance matrix of A and D.

My attempt is based on eigendecomposition
$$ M=Q \Lambda Q^T $$
and
$$
M=\begin{bmatrix}
a & b \\
c & d \\
\end{bmatrix}
\begin{bmatrix}
a & b \\
c & d \\
\end{bmatrix}
$$

But it lead to something very complicated.

I really thank you all for your answer!:)

All the best

GoodSpirit
 

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