Stability of Solution: Proving Stability for Continuous Functions

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The discussion focuses on proving the stability of a solution for a system of continuous functions defined by the equations \(\dot{x} = -a^2(t)y + b(t)\) and \(\dot{y} = a^2(t)x + c(t)\). The user, Rayne, seeks clarification on treating the matrix \(A = \begin{pmatrix} 0 & -a^2(t) \\ a^2(t) & 0 \end{pmatrix}\) as a constant matrix and the implications of the external inputs \(b(t)\) and \(c(t)\). The conversation suggests exploring Lyapunov functions and integrating factors to demonstrate stability, emphasizing the need for a deeper understanding of control theory concepts.

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Homework Statement


Let a(t), b(t) and c(t) be continuous functions of t over the interval [0,\infty). Assume (x,y) = (\phi(t), \psi(t)) is a solution of the system
\dot{x} = -a^2(t)y + b(t), \dot{y} = a^2(t)x + c(t)

Show that this solution is stable.

The Attempt at a Solution


I rearranged the system to get

\frac{d}{dt}\binom{x}{y} = \binom{-a^2(t)y + b(t)}{a^2(t)x + c(t)}<br /> = \left( \begin{array}{cc} 0 &amp; -a^2(t) \\ a^2(t) &amp; 0 \end{array} \right)\binom{x}{y} + \binom{b(t)}{c(t)}

I've only dealt with constant coefficient linear systems before, so I'm having trouble with this question.

Let A = \left( \begin{array}{cc} 0 &amp; -a^2(t) \\ a^2(t) &amp; 0 \end{array} \right).

I'm not sure if I can treat A like a constant matrix, i.e. take the determinant of A to be a^4(t) and trace(A) = 0 by treating t as constant. Also, what role does the \binom{b(t)}{c(t)} play here?

Can someone please help me?

Thank you.

Regards,
Rayne
 
Last edited:
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Do I need to find a Lyapunov function?
 
Couldn´t you just find an integrating factor h integrate the whole thing and find an integral expression for the whole thing.
Then you got the time T operator differentiate ( take integral sign away) and show that your solution is an eigenvector with Eigenvalue(floquet multiplier) = 1 for the system?
 

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