1. The problem statement, all variables and given/known data We mix 1 kg of ice at -10 C with 5 kg of vapor at 110 C. Calculate the temperature of equilibrium. m_i = 1 kg T_i = -10 C m_v = 5 kg T_v = 110 C L_melting = 330 000 J/kg L_condesation = 2 260 000 J/kg c_water = 4200 J/kg 2. Relevant equations Q_given = Q_got Q = L*m = c*m*dT 3. The attempt at a solution I do not know that at what state will be the water at the temperature of equilibrium. If it was water, if would be at 520 C. It can't be vapor because if the vapor gave energy to the ice to melt, then boil, the vapor would already start the condensation.