Static and Kinetic Friction Problem, getting wrong answer?

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The discussion revolves around a static and kinetic friction problem involving a crate of oranges on a truck. The user is calculating the frictional force acting on the crate, initially using the static friction coefficient but receiving incorrect feedback from an online assignment. For part b, they attempt to calculate the friction force during acceleration but also receive an incorrect result despite using the kinetic friction value. The user successfully determines the maximum acceleration the truck can have without the crate sliding, identifying it as 3 m/s². The conversation highlights confusion regarding the crate's acceleration while the truck moves at a constant velocity.
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A crate of oranges weighing 176 N rests on a flatbed truck 2.0 m from the back of the truck. The coefficients of friction between the crate and the bed are μs = 0.30 and μk = 0.20. The truck drives on a straight, level highway at a constant 6.3 m/s.

a. What is the force of friction acting on the crate?
I multiplied .30 X 176= 52.8. Online assignment says it's wrong?

frictional force= co of friction times Normal force

b. If the truck speeds up with an acceleration of 4.0 m/s2, what is the force of the friction on the crate?

magnitude:
Direction:

I simply used the kinetic friction value times the normal force and still got it wrong.


frictional force= co of friction times Normal force

(c) What is the maximum acceleration the truck can have without the crate starting to slide?

I got this right at 3 m/s
 
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Alright, I got B and C, but I still can't get a.
 
The truck and the crate move together with a constant velocity along a straight line. Does the crate accelerate?

ehild
 

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