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Static equilibrium

  1. Oct 23, 2014 #1
    1. The problem statement, all variables and given/known data
    A rope of negligible mass is stretched horizontally between two supports. When an object of weight 3160N is hung at the centre of the rope, the rope is observed to sag by 35.0cm. What is the tension in the rope?

    Problem 5.png
    2. Relevant equations


    3. The attempt at a solution

    Sum of forces in x-direction: ∑Fx = Fx2 - Fx1 = 0

    Sum of forces in y-direction: ∑Fy = Fy1 + Fy2 - W = 0

    Sum of torques: I chose the axis to be through the point attached to the left support, resulting in

    L.Fy2 - 1/2L.W - 0.35Fx2 = 0

    And at this point my efforts literally come to nought, because with Fy1 = Fy2, the terms in L in the torques equation cancel each other. I can see that by finding the angle between the rope and the horizontal it's possible to get the tension, which is T = 7920N. However this approach will not suffice for more advanced problems. So my question is, where am I going wrong here?
     
  2. jcsd
  3. Oct 23, 2014 #2

    SteamKing

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    It's not clear what 'more advanced problems' you are worried about.

    A rope can only support a tensile force; therefore writing a moment equation in this case is unnecessary.
     
  4. Oct 23, 2014 #3
    Ah, I see. This is why learning on one's own can be such a pain. Good thing Physics Forms is here to clear things up. Thank you.
     
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