STATICS: Applying Force Equilibrium

AI Thread Summary
The discussion focuses on solving a statics problem involving a ball held by an inclined surface and a compressed spring. The key steps include analyzing the free body diagram (FBD) and applying the equilibrium condition that the sum of forces in both the x and y directions equals zero. The weight of the ball (W) primarily influences the y-direction, while the spring force and the normal force from the inclined surface affect the x-direction. Participants emphasize the importance of determining the angle of the normal force to apply trigonometric functions effectively. Ultimately, the original poster successfully resolved their confusion and solved the problem.
spragumn
Messages
2
Reaction score
0
The ball of weight W is held in place as shown in the left figure by the inclined surface and the compressed spring. The FBD of the ball is shown in the right figure.
Determine the force exerted by the spring on the ball, and the force exerted by the inclined surface on the ball in terms of the weight, W, of the ball.

How would this problem be solved?
I have the FBD, I'm just unsure of the first step!
 

Attachments

  • statics.gif
    statics.gif
    5.7 KB · Views: 914
Last edited:
Engineering news on Phys.org
The sum of the forces in x and y=0. So for example w is only affecting the sum in y, and s only in x. You would have to find the angle of the normal force and then you can express everything with cosines and sines. Give it a try, and if you don't have a clue just yet, post another message here with what you have done so far.
 
I was thinking about the problem wrong. Thank you for your guidance! I was able to figure it out.
 
Thread 'Physics of Stretch: What pressure does a band apply on a cylinder?'
Scenario 1 (figure 1) A continuous loop of elastic material is stretched around two metal bars. The top bar is attached to a load cell that reads force. The lower bar can be moved downwards to stretch the elastic material. The lower bar is moved downwards until the two bars are 1190mm apart, stretching the elastic material. The bars are 5mm thick, so the total internal loop length is 1200mm (1190mm + 5mm + 5mm). At this level of stretch, the load cell reads 45N tensile force. Key numbers...
I'm trying to decide what size and type of galvanized steel I need for 2 cantilever extensions. The cantilever is 5 ft. The space between the two cantilever arms is a 17 ft Gap the center 7 ft of the 17 ft Gap we'll need to Bear approximately 17,000 lb spread evenly from the front of the cantilever to the back of the cantilever over 5 ft. I will put support beams across these cantilever arms to support the load evenly
Back
Top