Statics: Bending of a beam/evenly distributed force problem

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SUMMARY

The discussion focuses on calculating the largest bending stress, σb, in a beam subjected to an evenly distributed force (q). The specific equation used for bending moment at incision 2 is Mb = FA*aA - q*2.5m*1.25. The term 1.25 is clarified as a factor related to the geometry of the beam and the distribution of forces. Participants emphasize the need to define symbols such as aA and Mb, and suggest starting with the bending moment equations for sections 16.2 and 16.3, using x as the horizontal axis.

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hattori_hanzo
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Hello, and sorry for my English, as I am Norwegian.

I have a statics problem which I can not understand.

I've taken a pic from my book:
eFcrt.jpg


The problem asks me to find the largest bending stress, σb, in the incisions 1 and 2.

I have the solution in front of me, I just don't understand what they have done with the evenly distributed force (q). Especially in incision 2, when they find Mb, they have used: Mb = FA*aA-q*2.5m*1.25.

The q*2.5m I can understand, but where does the 1.25 come from? I thought it should be divided by 2?

Can someone explain how this works for me?
 
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Especially in incision 2, when they find Mb, they have used: Mb = FA*aA-q*2.5m*1.25.

Please confirm what the symbols stand for.

In particular what is aA and Mb ?

You have not provided symbols for the reactions at A and B?
Do you know how to calculate these reactions?

You should start by writing the equation for the bending moments for 16.2 and 16.3, using x for the horizontal axis and starting with x=0 at A. Can you do this?
It will have the form M = some function of x and the loads to the left of x.
 

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