(STATISTICS) 3 randomly selected observations from standard norm dist

AI Thread Summary
To find the probability that the sum of three randomly selected observations from a standard normal distribution is less than 2, one must first understand how to combine normal distributions. The sum of independent normal variables is also normally distributed, with the mean being the sum of the means and the variance being the sum of the variances. For three standard normal variables, the mean is 0 and the variance is 3, leading to a new normal distribution for the sum. The probability can then be calculated using the cumulative distribution function (CDF) for the resulting normal distribution. The final answer is approximately 0.874928, indicating a high likelihood that the sum is less than 2.
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Homework Statement



3 randomly selected observations form the standard normal distribution are selected. What is the probability that their sum is less than 2?

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The Attempt at a Solution



I know that the answer is 0.874928, but I don't know how to get that.


In my mind, you would say that 2/3=0.67, so what is the probability that the average of the 3 values is less than 0.67?

This gets me the wrong answer however.
 
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How do you add normal distributions?
 
I think what the question is asking, is that 3 random numbers are chosen FROM a standard normal distribution. It's then asking what the chances are that their sum is less than 2.
 
Same thing.
The numbers are x,y, and z - their possible values are distributed normally with mean 0 and standard deviation 1.

the sum of them is s=x+y+z ... s has a range of possible values too.
You need to find how s is distributed, it's pdf, so you can find P(s<2). How do you add normal distributions?
 
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