Stats question , have work and answer shown

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The problem involves calculating a glucose level L, where the mean glucose level of four test results has only a 0.05 probability of exceeding L. The normal distribution is given with a mean (μ) of 125 mg/dl and a standard deviation (σ) of 10 mg/dl. The correct formula to use incorporates the sample size, adjusting the standard deviation to σ/√n, which in this case is 10/√4 = 5. The user initially calculated L as 130.199 but was unsure if the sample size affected the calculation. Understanding the impact of sample size on the standard deviation is crucial for accurate results.
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Homework Statement



i didnt know which forum stats is posted in so i posted it here, but the problem says the q is , Sheilas measure glucose level one hour after a sugary drink varies according to the normal distribution (u= 125 mg/dl) and r=10 mg/dl. What is the level L such that there is a probability only 0.05 that the mean glucose level of 4 test results falls above L?

Homework Equations



x= u(mew) + z*r

The Attempt at a Solution


I did a backwards normal calculation of x= 125 + .5199 (from table A probs) * 10 = 130.199

i think its right but i dunno, does the 4 play a part in my equation or is this the wrong way to do it? ANY information would be helpful
 
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Yes, it does. The average of n samples from a population with mean mu and standard deviation \sigma is normally distributed with mean mu and standard deviation \sigma\sqrt{n}. Notice that means that the larger sample you have the smaller its standard deviation is and the more "accurate" it is.
 
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