Steady State Solution for Damped System with External Forcing

FHamster
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Homework Statement



Find the steady-state solution having the form https://webwork3.math.ucsb.edu/webwork2_files/tmp/equations/e1/348e8eb8a4ddf62dd06b46276196e71.png for the damped system x'' + x' + x = 2cos(3t)

Homework Equations



Acos3t + bsin3t

The Attempt at a Solution



To be honest, I wasn't sure how to do this problem, so I just tried undetermined coefficients and got (-16/73)cos(3t)+ (6/73)sin(3t), which was wrong :< muuu
 
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FHamster said:
To be honest, I wasn't sure how to do this problem, so I just tried undetermined coefficients and got (-16/73)cos(3t)+ (6/73)sin(3t), which was wrong :< muuu

Why is (-16/73)cos(3t)+ (6/73)sin(3t) less than the variable "muuu"?
 
FHamster said:

Homework Statement



Find the steady-state solution having the form https://webwork3.math.ucsb.edu/webwork2_files/tmp/equations/e1/348e8eb8a4ddf62dd06b46276196e71.png for the damped system x'' + x' + x = 2cos(3t)

I just tried undetermined coefficients and got (-16/73)cos(3t)+ (6/73)sin(3t), which was wrong :< muuu

It is the correct steady-state solution, but you need to convert it to the given form xss=Ccos(3t-δ).


ehild
 
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Acos(\omega t- \delta)= Acos(\delta)cos(\omega t)- Asin(\delta)sin(\omega t)
With \omega= 3. What are A and \delta?
 
yo need to calculate the particular integral of it.
WHICH WILL BE
2cos(3t)/(D^2+D+1)
where D is what I think you can guess.multiply and divide by D^2-D+1 on left.the denominator will contain only even powers of D.put D^2=-9 in denominator and carry out the differentiation in numerator after that to find the result and if you don't get it see any book on differential eqn to find out the P.I. of it.C.F.will not contribute because it will be zero in steady state.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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