Steady state transition matrix

Elpmek
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Ok, I'm lost. I've an exam coming up so could so with a speedy reply.

This whole transition matrix stuff is not explained at all in our lecture notes. Here's an example question:

"Suppose that a country has a fixed number of voters, all of whom vote for
either party D or party R. Every year, 1/4 of D voters change to party R and 1/3 of R voters switch to party D. Let xn and yn represent the proportions of
D and R voters respectively after n years (so that xn + yn = 1).
(a) Find the transition matrix T for this process.
(b)Explain the term ”steady state”, and find the steady state in this problem.
(c)Show that xn and yn tend to the steady state values as n goes to infinite, regardless
of the values of x0 and y0."

I don't even know what the matrix is suppose to look like...
 
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The matrix is will have: (3/4 1/3) on the top row and (1/4 2/3) on the bottom row. Do you see why? If you multiply this by the vector (D, R) you get the specified voter switches.

Usually when you are asked to find a steady-state vector one of the eigenvalues of the matrix will be 1, and you need to find the eigenvector corresponding to this eigenvalue. The reason this is called a "steady-state" vector is that the transition matrix does not change it.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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