Steps for calculating dc generator output potential

Click For Summary
SUMMARY

This discussion focuses on calculating the output potential of a DC generator using specific parameters related to wire and magnet properties. The user provided detailed specifications, including the use of AWG 24 enamel copper motor wire, a coil RPM of 18,364,800, and neodymium magnets with a pull force of 705.23 lbs. Key calculations suggested include determining the weight of copper wire, the number of moles of copper, and the total number of electrons in the circuit. The conversation emphasizes the importance of understanding the generator's design, including whether it utilizes a commutator or slip rings.

PREREQUISITES
  • Understanding of electromechanics and DC generator principles
  • Familiarity with wire properties, specifically AWG 24 enamel copper motor wire
  • Knowledge of magnet properties, particularly neodymium magnets
  • Basic grasp of electrical calculations, including volts, watts, and amps
NEXT STEPS
  • Calculate the output voltage and current using Faraday's Law of Electromagnetic Induction
  • Research the impact of coil RPM on generator output
  • Learn about the role of commutators and slip rings in DC generators
  • Investigate the effects of magnetic field stacking on output potential
USEFUL FOR

Electrical engineers, electromechanics students, and hobbyists interested in DC generator design and output calculations will benefit from this discussion.

Xeromyr
Messages
3
Reaction score
0
I need help understanding a few different items regarding electromechanics, and I'm not really sure where to start. Though the figures I have provided immediately seem impractical (coil melt down, coil explosion due to excessive rpm, inside dimensions exceeding their respective outside dimensions when certain figures are added together, ect), they are the numbers I must work with.

Wire properties:
Enamel copper motor wire.
AWG 24 (0.0201 in dia).
Wire length: 40,000 feet
Turns of wire in coil: 46462.84
Coil RPM: 18,364,800
Coil distance from magnets: .05 inches

Magnet properties:
Material: Neodymium
Pull Force: 705.23 lbs
Surface Field: 5630 Gauss
Brmax: 14,800 Gauss
BHmax: 52 MGOe

I am unsure if magnetic fields "stack" (double, triple, ect) when they are close or put together, but if they do then assume that two of those magnets are .6 inches in distance from and parallel to, each other. Also assume that the coil is .5 inches in width and would be between those magnets.

Basically, how would I even start calculating the types of output this would generate? Volts, watts, amps -- you name it.

Thanks in advanced. :)

Edit:
Do you think the appropriate first steps would be something along the lines of this.
Calculate weight of copper mole: 63.549g
Calculate copper weight of wire: 22188.650118g
Divide weight of mole by total weight of wire to get number of moles: 349.174615
Multiply number of moles by Avogadro's Number to get number of total atoms (6.02)(10^23):
Multiply number of total atoms by number of electrons in a single atom to get total number of electrons in circut (29):
Calculate percent error:
 
Last edited:
Engineering news on Phys.org
Bump?
 
What are dimensions of this generator? Is the copper wound on a stator or on an armature? Does the generator have a commutator or slip rings on the armature? Does the generator have diode rectifiers (like an automobile)? Does the generator have a neodymium magnet armature? Do you commutate the exciting current with a Hall effect probe? Your RPM is much too high.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
6K
Replies
8
Views
3K
  • · Replies 16 ·
Replies
16
Views
12K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 2 ·
Replies
2
Views
8K
  • · Replies 27 ·
Replies
27
Views
5K
Replies
17
Views
3K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 38 ·
2
Replies
38
Views
8K