Stewart's Calculus, 5th Edition

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We are using Stewart's Calculus 5th edition in a course I'm taking this term and I need a little assistance. My copy hasn't arrived yet, and I need to get started. I have the 3rd edition, so I've read the sections required, but I don't have the 5th edition, so I don't have the problems.

If anyone has the 5th edition and would be willing to email or PM me a few of the problems from the text (just problems, not solutions), I would be very grateful.

Thanks in advance,
Jeff
 
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What are you looking for. The 5th and 3rd edition are very similar, I've used the 3rd edition while my friend had the 5th.
 
I need the following exercises in section 2.2 from the 5th edition: 1, 3, 7, 9, 13, 17, 19, 21, 25, 27, 31, 35. The text matches from the 3rd to the 5th edition, but the exercises are different.
 
Give me an hour or so, i don't have a scanner so i'll have to transribe everything into derive. In case you don't have it.
http://www.chartwellyorke.com/derive.html

nevermind i found a webcam in my closet
-Nick
 
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Thanks nsimmons. I appreciate your willingness to help
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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