Stone Dropping vs Ball Throwing

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The discussion focuses on calculating the maximum height of a stone thrown upward with an initial speed of x m/s, while a ball is dropped from a height of 55.9 m. Participants emphasize the need for the kinematic equations to describe the motion of both the stone and the ball. The initial speed of the stone is a variable that affects its maximum height, which can be expressed in terms of x. The conversation highlights the importance of understanding these equations to solve the problem effectively. Overall, the thread seeks clarity on the relationship between the stone's initial speed and its maximum height.
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A stone is thrown upward from the ground with an initial speed of x m/s; at the same instant, a ball is dropped from a tower 55,9 m high. Ball and stone will hits in height what is the maximum height of the stone.

What is the intial speed of stone?


I'm sorry about my really bad English...:cry:
 
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In this question they will probably want you to give the equation for maximum height in terms of x. This is so you can put any starting speed in and come up with a maximum height.
 
can anyone help with this equation?

i sucks really much with this...
 
We can't give you an answer. Are you familiar with the kinematic equations? What equations will describe the motion of the ball and the motiopn of the stone?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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