Calculate Strain of a Cable: 10-m Long w/ 25-N Sign

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    Cable Strain
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To calculate the strain in the 10-m long cable with a 25-N sign, use the formula for strain, which is ΔL/L0. Here, ΔL is the change in length (2.5 cm or 0.025 m) and L0 is the original length of the cable (10 m). The strain can be calculated as 0.025 m / 10 m, resulting in a strain of 0.0025. Additionally, understanding the geometry of the cable's sagging may help clarify how to approach the problem. The focus should remain on applying the strain formula correctly to find the solution.
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A 10-m long cable has a "No Hippos in the Pool" sign weighing 25-N suspended from the middle of the cable. The cable stretches by 2.5 cm. What is the strain in the cable?

I know strain is ΔL/L0, but don't really know how that plays out in this scenario. If you could give me the first step or so, that'd be great!
 
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pippintook said:
A 10-m long cable has a "No Hippos in the Pool" sign weighing 25-N suspended from the middle of the cable. The cable stretches by 2.5 cm. What is the strain in the cable?

I know strain is ΔL/L0, but don't really know how that plays out in this scenario. If you could give me the first step or so, that'd be great!

ΔL/Lo is strain, so it looks to me like that's all you need to do.

Strain is a measure of geometrical deformation right?
 
Well, my problem is more how I find L than how to find strain I guess.
 
pippintook said:
Well, my problem is more how I find L than how to find strain I guess.

It's not 10m ?
 
Draw a FBD showing the sagging cable and do a bit of geometry.
 
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