Max Compressive Stress in Cane: 0.00245 MPa

[uno]

1. A man leans down on a cane with a vertical axial force of 98 N. The narrowest part of the cane has a cross-sectional area of 4.0 cm2. What is the maximum compressive stress in the cane in MPa



2. Stress = F/A



3. I first changed 4.0cm^2 to .04m^2. I then took 98N/.04m^2 = 2450 Pa which equals .00245 MPa, but the answer is incorrect. Please let me know what I am missing. Thanks.

 

[mathmate]

I first changed 4.0cm^2 to .04m^2.

To convert cm² to m², try it this way:

1 cm² = (1/100m)²=0.0001 m²

 

[thomate1]

The calculation for the maximum compressive stress in the cane is correct. However, it is possible that the given value of 0.00245 MPa is not the maximum compressive stress in the cane, but rather a different value such as the average or nominal stress. It is also important to note that the given value may be rounded and may not be an exact value. Additionally, there could be other factors that affect the stress in the cane, such as its material properties and any imperfections or defects. It would be helpful to have more information about the specific cane in question in order to accurately determine the maximum compressive stress.