(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A draw bar between a tractor and trailer is made from a length of steel bar 0.08m by 0.012m rectangular cross-section. The load is transmitted by means of a 0.015 diameter pin at each end. Determine the maximum stresses in the bar and pin if the axial load is 10,000N

2. Relevant equations

σ=F/A

ε=ΔL/L

τ=F_{s}/A

3. The attempt at the solution

Area of steel cross-section = 0.08x0.012=9.6x10^{-4}

Stress is bar = F/A

= 10000/9.6x10^{-4}

=10.42x10^{6}

Shear in Bolt = F_{s}/A A = ∏d^{2}/4

=1.767x10^{-4}m^{2}

Shear in bolt = 10000/1.767x10^{-4}

=56.588 x 10^{6}

But thats the shear in one bolt so surely the max shear is 2x that which would be113.2MPA

Both values aren't the same as the ones in the back of the book so i'm not sure where I've gone wrong

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# Homework Help: Stress + Shear stress

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