Struggling with Homework Equations? Get Help Here!

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The discussion revolves around solving a homework problem related to current density and its integration. The user struggles with finding the correct denominator value in the equation J = i/A and seeks clarification on the integration process. After some back-and-forth, it is clarified that the total current i can be calculated by integrating the current density over the area, leading to the correct expression. The final solution for the total current is derived as i = (J_o * 2π * R^2) / 3. The user expresses gratitude for the assistance received in understanding the integration steps.
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Homework Statement



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Homework Equations



J=i/a

The Attempt at a Solution



Studying for a test. This sample exam went pretty well. I am having trouble with 3 out of the 20. I can't figure this one out. I can't seem to find how to get a denominator value.

The answer is B.

I know that current density is equal to the current over the area.
J=\frac{i}{A}
J_o(r/R)=\frac{i}{\pi (\frac{r}{R}^2)}

I know I'm doing something wrong. Anyone help?
 
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You are right at this formula:

<br /> J = \frac{i}{A}<br />

But it is just the special case of this:

i = \int JdA
and dA = 2 * pi * r * dr.
 
Oh. Right.

I still don't know how to get a correct answer out of that.

i = \int J \cdot da

i = \int_0^r \frac{J_or}{R} \cdot 2\pi r dr

pulling out the constants:

i = \frac{J_o2\pi}{R} \int_0^r r^2 dr

i = \frac{J_o2\pi}{R}\frac{r^3}{3}|_0^r

i = \frac{J_o2\pi}{R}\frac{r^3}{3}

Where's the extra r in the numerator coming from?
 
When you set r = R, you will get what you want (because problem asks you to find total current, not current at radius r, i think).
 
Last edited:
Oh. because I'm integrating from a radius of 0 to a radius of R. That makes sense.

<br /> i = \frac{J_o2\pi}{R}\frac{r^3}{3}|_0^R<br />

<br /> i = \frac{J_o2\pi}{R}\frac{R^3}{3}<br />

<br /> i = \frac{J_o2\pi R^2}{3}<br />

Thanks :)
 
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