q) A force F acts on a block of mass m placed on a horizontal smooth surface at an angle Θ with horizontal. Then (A) If F sinΘ < mg then a = (F + mg) / m (B) Acceleration = FcosΘ/m where, F > mg cosecΘ (C) Acceleration = F/m if FsinΘ > mg (D) If F SinΘ > mg then a = (F + mg) / m my work -------- on drawing the F.B.D we we get.. clearly there will be linear and vertical acceleration as well... Now if F sinΘ > mg then the Normal force will be 0 => F sinΘ - mg = may ---- (i) and, F cosΘ = max ------ (ii) Adding the two eqns. we get, F sinΘ + F cosΘ - mg = m (ax + ay) or, ax + ay = (F - mg) / m but the correct option is d. couldn't represent vectors with their notations so please understand it urselves. Am i wrong? if yes then where and why? Thanks in advance...!!