Stuck on an Area Between Curves Question

Camronnba
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I have been asked to find the area between the following curves
f(x)= x^3 -9x^2 +18x and
g(x)= (-x)^3 +9x^2 -18x

I started out by finding the points of intersection, which I found to be 0, 3, and 6. I then integrated |f(x)-g(x)|and evaluated between 6 and 0. I got an answer of zero but it says I am wrong. I then tried evaluating between 0 and 3, and 3 and 6 and adding those together, again I get zero. After that I brought out my graphing calculator, and after viewing the graphs, 0 seems like a logical answer. I must be making a mistake somewhere, if someone could please steer me in the right direction it would be greatly appreciated. Thanks
 
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Nevermind, I should really pay attention to absolute value signs when I see them. haha
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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