Velocity and Acceleration Calculations for a Slowing Truck | Homework Help

AI Thread Summary
The discussion revolves around solving physics problems related to velocity and acceleration for a truck and a jet plane. For the truck, the original speed was calculated to be 7.65 m/s with an acceleration of -0.70 m/s² as it slowed down over a distance of 40.0 m. The jet plane, landing at 117 m/s with a maximum deceleration of -5.80 m/s², requires a minimum time to come to rest, which can be determined using kinematic equations. Additionally, the minimum distance needed for the plane to stop is assessed to determine if a 0.800 km runway is sufficient. The participants successfully solved both problems, confirming their understanding of the concepts.
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I been stuck on this homework problem for about an hour.

A truck covers 40.0 m in 8.25 s while smoothly slowing down to final speed of 2.05 m/s.

(a) Find the truck's original speed.
m/s

(b) Find its acceleration.
m/s2

I was told to use this V^2 = Vo^2 + 2AdeltaX but became lost.
 
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Okay, I finally just figure out how to do this and got the answer

a. 7.65m/s and b. -.70

A jet plane lands with a speed of 117 m/s and can accelerate at a maximum rate of -5.80 m/s2 as it comes to rest.

(a) From the instant the plane touches the runway, what is the minimum time needed before it can come to rest?
s
(b) Can this plane land on a small tropical island airport where the runway is 0.800 km long?
yes
no
What is the actual minimum distance needed to stop the plane?
km

Can anyone help me with that?
 
a) just requires a straight application of v=v_0 +a t

b) after solving part a, you'll have the time, use that along with velocities (initial and final) in another common kinematics equation, and solve for distance. Then you'll know if .8km is long enough AND you'll have the answer for the 2nd part of b.
 
Thanks for the help and I was able to solve this.
 
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