Stuck on this downhill skiier problem help

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A skier reaches a speed of 56 m/s on a 30-degree slope, and the problem involves calculating the minimum distance traveled along the slope from rest, ignoring friction. The key to solving this problem is to find the acceleration down the slope by resolving gravitational acceleration into components. Using the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, and a is acceleration, allows for the calculation of distance. The skier's acceleration can be determined using the sine of the slope angle. The solution involves two steps to arrive at the final answer.
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Homework Statement



A sker reaches a speed of 56 m/s on a 30 degree ski slope. Ignoring friction, what was the minimum distance along the slope the skier would have had to travel, starting from rest?

Homework Equations



Which equation do i start with? I'm pretty sure i have to find the x-y component of the acceleration but I'm not sure I'm flat out stuck on this problem.


The Attempt at a Solution



If i draw a right triangle, and the opposite leg is -9.8 m/s do i use sin30 to find the acceleration down the slope?
 
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You can resolve it in a way that is parallel and perpendicular to the ski slope. So find acceleration and then use the formula v^2 = u^2 + 2as to solve it.
 
i figured it out. it was two steps
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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