Submerged Fraction of Hollow Glass Sphere

AI Thread Summary
The discussion revolves around calculating the submerged fraction of a hollow glass sphere in a liquid denser than the glass. The problem involves determining the balance between buoyant force and the weight of the shell, with the user initially arriving at an incorrect submerged fraction of 0.48 instead of the expected 0.28. Clarification is sought regarding the interpretation of "fraction submerged," with participants agreeing it refers to the volume of the sphere. The conversation highlights the importance of accurately calculating the volume of the shell and the displaced fluid. Ultimately, the user resolves the confusion and finds the correct solution.
Fruityloop
Messages
4
Reaction score
0

Homework Statement



A hollow, spherical glass has an inner radius of R and an outer radius of 1.2R. The density of the glass is d. What fraction of the shell is submerged when it floats in a liquid of density ρ = 1.5d (1.5 times the density of the glass)? (Assume the interior of the shell is a vacuum.)

Homework Equations



W=ρgh
Volume Sphere = (4/3)πr^3

The Attempt at a Solution



I attempted to set the weight of the water displaced equal to the weight of the shell. (Sum of forces = 0, Bouyont Force - Mass of Shell = 0, BF = Mass of Shell. For weight of shell I used W=ρgh with the volume being the volume of a sphere with r of 1.2R minus volume of a sphere with r of R. For the volume of water displaced I just used some variable fraction multiply by the volume of a sphere equation. ds and Rs then cancel out. I know the answer I'm supposed to get is 0.28, but I keep getting 0.48. Any insight towards a full solution would be hugely appreciated!
 
Physics news on Phys.org
The fluid is not water. You have to take its density into account.

ehild
 
I think I took that into account. I had it set up;

BF=Weight of Shell
ρgh (liquid) = ρgh (shell)

(1.5)dgh = dgh

d cancels?
 
What is h? You need to use the volume of the shell to get the weight of the shell and the volume of the outer sphere to get the weight of the displaced fluid.

ehild
 
Oh sorry stupid typo. h is supposed to be V. I am fallowing you, that was my logic. I just don't know how to get from there to my answer >.<
 
The volume of the shell is not the same as the volume of the outer sphere.

ehild
 
Just to add a little noise into the relative peace and calm, when the problem statement asks for "What fraction of the shell is submerged", does it mean what fraction of the mass of the shell is submerged, what fraction of the volume of the shell (sphere!) is submerged, what fraction of the surface area of the shell is submerged, or what fraction of the diameter of the shell is submerged? :devil:
 
gneill said:
Just to add a little noise into the relative peace and calm, when the problem statement asks for "What fraction of the shell is submerged", does it mean what fraction of the mass of the shell is submerged, what fraction of the volume of the shell (sphere!) is submerged, what fraction of the surface area of the shell is submerged, or what fraction of the diameter of the shell is submerged? :devil:

It is fraction of the volume of the sphere, according to the "supposed" answer, but you are right, the question is not clear.

ehild
 
Thanks for the help. I figured it out. @gneill, it is such an elusive question. I wasnt sure exactly what it was asking either.
 
Back
Top