Successfully Completed Egg Project: Seeking Input

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    Egg Input Project
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The discussion centers on seeking advice for a successful egg drop project, with emphasis on design criteria such as drop height and protective measures for the egg. Participants share their experiences, noting the importance of managing momentum during the drop, specifically through altering the time of impact or the force exerted on the egg. One contributor mentions a related experience with a water balloon competition, highlighting the fragility of the egg compared to other objects. The thread encourages further exploration of innovative solutions to extend the time of impact without using a parachute. Overall, the conversation aims to gather insights for improving egg drop project outcomes.
deficiency4math
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Hi,

if anyone has successfully done an egg project like this, I would really appreciate any input.

The thread is in the general engineering section.



thanks
 
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I did this a few years ago although my model wasn't very good. What are the criteria for your drop? Height, size of protection for egg, etc.
 
Well, not quite an egg drop competition, but I had a water balloon competition
I know that the egg is more fragile.

Basically, since the momentum when the egg hits the floor is very high
(remember the momentum equation?)
Well, just for in case,
p = mv, and the impulse,
I = F \Delta T = \Delta p

You can change the momentum if you either change the time(time it takes to hit the ground), or force(basically how hard it hits the ground)

If you CANNOT use a parachute like me, the only thing you can change is \Delta T

Can you thing of a way to do that? :smile:
 
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Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

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