Sum of Series (1/n^2) Approximation & Error Estimation

remaan
Messages
132
Reaction score
0

Homework Statement



Using the sum of the first 10 terms ,
Estimate the sum of the series (1/n^2) n from 1 to infinity ? How good the estimate is ?

c) Find a value for n that will ensure that the error in the approximation s= sn is less than .001.

Homework Equations



I think Rn = s - sn

The Attempt at a Solution



Am ok with that, but how to know who good the appr. is ??
And do we do the integration to find the value of n ? if so please tell how ?
 
Last edited:
Physics news on Phys.org
Check your book for a remainder theorem associated with the integral test. Is it there?
 
Uha, I think that you mean this formula

Sn+ ∫_(n+1 )^(infity )▒〖f(x)dx<s<Sn+ ∫_n^(infinity )▒f(x)dx〗

Do you think that this works for part c ?
 
Your equation doesn't appear as it should on my browser, but there's a simple theorem for estimating the remainder R_N that exists when the nth partial sum S_N of a convergent series is computed. It says:

R_N\leq a_N+\int_N^{\infty}f(x)dx

And yes, it will help for part c.
 
Uha, thanks alot..

But, I still wondering when do we use two boundries and when to use only one when computing the error ??
 
You're not computing the error, you're estimating it. And any series that converges by the integral test has only positive terms. So there is always an implicit lower boundary of 0 on R_N.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top