Sum of Vector Spaces U & W in Linear Algebra Done Right

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SUMMARY

The sum of two subspaces U and W in the context of vector spaces is defined as U + W = {(x, y, 0) : x, y ∈ F}, as stated in "Linear Algebra Done Right" by Sheldon Axler. The discussion clarifies that the sum does not require the elements to be expressed in the form (x+y, y, 0), as the set of vectors generated by both forms is equivalent. This understanding resolves the confusion regarding the representation of the sum of subspaces in vector space V.

PREREQUISITES
  • Understanding of vector spaces and subspaces
  • Familiarity with the notation and concepts in linear algebra
  • Knowledge of the field F used in vector space definitions
  • Basic comprehension of vector addition and linear combinations
NEXT STEPS
  • Study the properties of vector space sums in "Linear Algebra Done Right" by Sheldon Axler
  • Explore examples of subspace sums in different vector spaces
  • Learn about linear combinations and their role in defining subspaces
  • Investigate the implications of the dimension theorem in linear algebra
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Students and educators in linear algebra, mathematicians exploring vector space theory, and anyone seeking to deepen their understanding of subspace operations and their properties.

airpocket
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The sum of two subspaces seems a simple enough concept to me, but I must be misunderstanding it since I don't understand why Axler gives an answer he does in Linear Algebra Done Right.

Suppose U and W are subspaces of some vector space V.

[tex]U = \{(x, 0, 0) \in \textbf{F}^3 : x \in \textbf{F}\} \text{ and } W = \{(y, y, 0) \in \textbf{F}^3 : y \in \textbf{F}\}.[/tex]

The sum is given as follows:

[tex]U + W = \{(x, y, 0) : x, y \in \textbf{F}\}.[/tex]

Whereas it seems to me it should be:

[tex]U + W = \{(x+y, y, 0) : x, y \in \textbf{F}\}.[/tex]

Am I misunderstanding the concept of sum, and it does not really mean that all the elements in [tex]U + W[/tex] should have the form [tex](x, 0, 0) + (y, y, 0)[/tex], or [tex](x+y, y, 0)[/tex]?
 
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since x can be anything, it can be anything -y, so the set of vectors of form (x,y) where x and y bare anything, is the same as the set of vectors (x+y,y) where x and y are anything.

so you are also right!
 
Thanks so much. That makes sense. I didn't think about simplifying x + y.
 

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