Surface formula identification

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SUMMARY

The equation 4x² + 4y² - 8y - z² = 0 represents a hyperboloid of one sheet. The standard form of this surface is x²/c² + y²/c² - z²/d² = 1, where c = 2. The transformation from the given equation to the standard form involves completing the square for the y term, resulting in the equivalent expression x² + y² - z²/2² = 1. This confirms that both equations describe the same surface.

PREREQUISITES
  • Understanding of conic sections and their equations
  • Knowledge of hyperboloids and their standard forms
  • Proficiency in algebraic manipulation, specifically completing the square
  • Familiarity with three-dimensional geometry
NEXT STEPS
  • Study the properties of hyperboloids, focusing on hyperboloid of one sheet
  • Learn how to complete the square in quadratic equations
  • Explore the geometric interpretations of conic sections in three dimensions
  • Investigate the applications of hyperboloids in physics and engineering
USEFUL FOR

Students studying advanced mathematics, particularly those focusing on geometry and algebra, as well as educators teaching conic sections and their applications.

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Homework Statement



Identify the surface given by the equation 4x^2 +4y^2 −8y −z^2 = 0.

Homework Equations



x^2/c^2 + y^2/c^2 - z^2/c^2 = 1

(textbook definition for hyperboloid of one sheet.

The Attempt at a Solution



I know just by looking at the textbook formula what surface this is. However, my professor gives the following answer for the problem..

It is a hyperboloid of one sheet, x^2 + y^2 − z2/2^2 = 1

I get what the surface is, I just don't understand how he algebraically changed the formula to the above solution..

is (4x^2 +4y^2 −8y −z^2 = 0 ) the same as (x^2 + y^2 − z2/2^2 = 1)?

thanks. :)
 
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complete the square on the y term.
 

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