Surfaces in Space / Vector-Valued Functions

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Homework Help Overview

The discussion revolves around sketching the space curve formed by the intersection of the surfaces defined by the equations z=x²+y² and x+y=0. Participants are exploring how to express this curve as a vector-valued function.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to sketch the intersection curve and is seeking to express it as a vector-valued function but encounters a mental block. Other participants suggest finding y in terms of t using the plane equation and then determining z.

Discussion Status

Some participants have provided guidance on how to proceed with the problem, particularly in expressing y and z in terms of the parameter t. The conversation reflects ongoing exploration of the problem without a definitive conclusion yet.

Contextual Notes

The original poster mentions a mental block, indicating a potential challenge in progressing with the problem. There is also a reference to having set aside the math for a period, which may affect the continuity of the discussion.

llauren84
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Homework Statement



Sketch the space curve represented by the intersection of the surfaces. Then represent the curve by a vector-valued function.


Homework Equations



Surfaces: z=x2+y2, x+y=0
Parameter: x=t


The Attempt at a Solution



So, I sketched the space curve represented by the intersection of the two curves. It's simply a parabola. However, I can't seem to think of how to put it into a vector-valued function. I'm getting a mind block. (Perhaps, before anyone answers this, I may come up with the answer.)
 
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Got it yet? You already have x=t. What's y in terms of t? (Put x=t into the plane equation). Finally z=?
 
So, it's just z=t2+(-t)2? and..no I didn't get it yet. I put down my math and did other things. Thanks =) So, it's r(t)=<t,-t,2t2>?
 
Last edited:
Yes, that's z.
 

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