1. The problem statement, all variables and given/known data A uniform rod of mass 1.2 kg and length 1.2 m is pivoted in the horizontal position as shown (black point). The rod is at rest and then released. The acceleration due to gravity is g = 9.8 m/s2. What is the angular speed (in rad/s, but do not include units) of the rod as it passes through the vertical position (when end marked B is at the bottom)? What is the linear speed of the bottom end of the rod (marked B) when it passes the vertical position?(in m/s, but do not include units) 2. Relevant equations 3. The attempt at a solution Used conservation of energy, m*g*h=.5*I*w^2. I calculated I to be .252 and used .3 for h. Solving for w, I got 4.83. Then used the formula v=wr and got v=2.898. What am I doing wrong?