Taking the derivative of a function (looks easy but I don't know how to do it)

appplejack
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Homework Statement


f(x) = x(x-5)^4


Homework Equations





The Attempt at a Solution


I used product rule and chain rule so,
1(x-5)^4 + 4x(x-5)^3(1)

The answer to this question is 5(x-5)^3(x-1). I left it like the answer above. I don't know how to expand (x-5)^4. Thanks.
 
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appplejack said:

Homework Statement


f(x) = x(x-5)^4


Homework Equations





The Attempt at a Solution


I used product rule and chain rule so,
1(x-5)^4 + 4x(x-5)^3(1)

The answer to this question is 5(x-5)^3(x-1). I left it like the answer above. I don't know how to expand (x-5)^4. Thanks.

Your differentiation looks right. Just factorise out the (x-5)^3 and you should be able to get it in that form.
 
appplejack said:

Homework Statement


f(x) = x(x-5)^4


Homework Equations





The Attempt at a Solution


I used product rule and chain rule so,
1(x-5)^4 + 4x(x-5)^3(1)

The answer to this question is 5(x-5)^3(x-1). I left it like the answer above. I don't know how to expand (x-5)^4. Thanks.

Don't expand (x-5)^4. Factor (x-5)^3 out of both terms of your answer and collect what's left.
 
No expansion is necessary, simply rewrite it as (x-5)(x-5)^3. Then you'll have a term x(x-5)^3 and -5(x-5)^3.
 
haha. Why didn't I see that? Thanks guys.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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