Tangent of plane to a given surface

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Homework Help Overview

The discussion revolves around finding the equation of the tangent plane to a given surface, with a focus on understanding the normal vector and parametric forms of the solution.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of the tangent plane and its normal vector, questioning whether a specific mistake was made in the parametric form of the solution. There are attempts to identify errors related to the constant term in the parametric equation.

Discussion Status

Participants are actively engaging with the problem, exploring different forms of the solution and questioning assumptions about the calculations. There is recognition of a potential oversight in the original poster's work, particularly regarding the inclusion of a constant term in the parametric representation.

Contextual Notes

Participants note the importance of ensuring that the parametric equation satisfies the given point on the surface, indicating that verification of the solution is a key aspect of the discussion.

gomes.
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[PLAIN]http://img35.imageshack.us/img35/2033/tangent.jpg

I managed to do the first part okay ---- said some stuff about 3x^2 and y^2 term, its not linear etc..

but I am stuck in the part in red. Is it supposed to be something about a normal vector? How do i know what is wrong? and what mistake was made?

I calculated the equation of the tangent plane and it is: z=12(x−2)−6(y−3)-1

and the tangent plane has normal vector (12,-6,-1) at (2,3) ----- could it be something to do with the part circled in red?
 
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gomes. said:
[PLAIN]http://img35.imageshack.us/img35/2033/tangent.jpg

I managed to do the first part okay ---- said some stuff about 3x^2 and y^2 term, its not linear etc..
That's not wrong, but it's not such a good answer either. There is a very specific mistake that the student is making here.

but I am stuck in the part in red. Is it supposed to be something about a normal vector? How do i know what is wrong? and what mistake was made?

I calculated the equation of the tangent plane and it is: z=12(x−2)−6(y−3)-1

and the tangent plane has normal vector (12,-6,-1) at (2,3) ----- could it be something to do with the part circled in red?
The second one is clearly an attempt at a solution in parametric form (as opposed to the Cartesian for of part "a"). The solution is very nearly correct too, but not quite. Why don't you attempt to derive a correct solution in parametric form and compare it with the given solution.
 
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uart said:
The second one is clearly an attempt at a solution in parametric form (as opposed to the Cartesian for of part "a"). The solution is very nearly correct too, but not quite. Why don't you attempt to derive a correct solution in parametric form and compare it with the given solution.


Thanks, i got (lamba, mu, 12lamba-6mu-7)

So can i say the student forgot to put/calculate in the -7 in the parametric form? At a glance, how would i know the student got it wrong? Because he didnt put in the -7?
 
gomes. said:
Thanks, i got (lamba, mu, 12lamba-6mu-7)

So can i say the student forgot to put/calculate in the -7 in the parametric form? At a glance, how would i know the student got it wrong? Because he didnt put in the -7?

Yeah at a glance just check whether or not the equation is satisfied at the given point (2,3,-1).

Normally with a parametric equation like this I like to keep it in an expanded form like :

(x,y,z) = (1, 0, 12)\, \lambda \, + \, (0, 1, -6) \, \mu \, + \, (2, 3, -1)

In this form it's really obvious that the student has forgotten the last "fixed point" term.
 

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