Tangent Plane to f(x,y) = sin(x)cos(y) at (π/3,π/2)

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To find the equation of the tangent plane to the function f(x,y) = sin(x)cos(y) at the point (π/3, π/2), it's essential to evaluate the function at that point first. The function definition indicates that g is defined as z - sin(x)cos(y), requiring three arguments to determine a value for g. After evaluating f(π/3, π/2), the next step is to use this value to find z, which will facilitate the tangent plane calculation. The discussion emphasizes the importance of correctly interpreting the function's definition in the context of the tangent plane equation. This approach will lead to the correct formulation of the tangent plane.
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Homework Statement


3a) Find the equation of the tangent plane to the function f(x,y) = sin(x)cos(y) at the point (∏/3,∏/2).


The Attempt at a Solution



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There is quite clearly a z in the definition. What's going on?
 
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It's the way you have g defined. According to the function definition, g := z - sin (x)*cos (y), so you need 3 arguments to specify a value for g.
 
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So if I evaluate the function f(x,y) = sin(x)cos(y) at the point (∏/3,∏/2) and then use that point to find my value of Z it should work?
 
Hey, give it a shot.
 

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